How can i do "-" * 60 for Unix command line

Question

If I want to print 60 dashes.

Somehow like

echo "-" * 60.

How can I do with this? Thanks.

For bash [stackoverflow.com/questions/5349718/how-can-i-repeat-a-character-in-bash] (http://stackoverflow.com/questions/5349718/how-can-i-repeat-a-character-in-bash) — miltonb, Apr 22 '16 at 00:06

score 3 · Accepted Answer · answered Apr 22 '16 at 00:51

3

printf "%*s" 60 "" | tr " " "-"

The printf command prints an empty string padded with spaces to fit a width of 60. Then tr converts the spaces to dashes.

This does not print a trailing newline. If you want one, add ;echo to the end of the command.

answered Apr 22 '16 at 00:51

glenn jackman

score 1 · Answer 2 · answered Apr 22 '16 at 00:06

1

printf '%s\n' $(dd if=/dev/zero count=60 status=none | tr '\000' '-')

answered Apr 22 '16 at 00:06

zwol

2 Answers2