Basic logging dictConfig in Python

Question

NOTE I'm aware of this answer but that doesn't work for me, I am hoping for a complete, self-contained working example.

I'm trying to replace logging.basicConfig with dictConfig in Python (2.7)

My understanding is basicConfig simply sets up the root logger: so I'm attempting to do the same with the dictConfig. That is, set up the root logger with a handler, and then all the loggers in my application will propagate up the root logger.

What's missing from the following snippet? The behaviour is the log file is created, but no output makes it. (I've tried various combos of setting levels, it doesn't appear to help)

import logging
log_dict = {
    'loggers': {
        'root': {
            'handlers': ['file_handler']
        }
    },
    'version': 1,
    'disable_existing_loggers': False,
    'handlers': {
        'file_handler': {
            'filename': 'c:/mylogfile.log',
            'class': 'logging.FileHandler'
        }
    }
}

logging.config.dictConfig(log_dict)
logging.info('THIS IS A TEST')
logging.shutdown()
exit()

Possible duplicate of [python: complete example of dict for logging.config.dictConfig?](http://stackoverflow.com/questions/7507825/python-complete-example-of-dict-for-logging-config-dictconfig) — user3159253, Apr 22 '16 at 06:29
Not a duplicate, as the linked ticket is not a complete, self-contained working example, and using the dict in that example doesn't work for me. — Zero, Apr 22 '16 at 06:33

score 7 · Accepted Answer · answered Apr 22 '16 at 07:04

The following code works perfectly for me:

import logging
import logging.config

log_dict = {
    'version': 1,
    'disable_existing_loggers': False,
    'formatters': {
        'standard': {
            'format': '%(asctime)s [%(levelname)s] %(name)s: %(message)s'
        },
    },
    'handlers': {
        'default': {
            'level': 'INFO',
            'formatter': 'standard',
            'class': 'logging.StreamHandler',
        },
        'file_handler': {
            'level': 'INFO',
            'filename': '/tmp/mylogfile.log',
            'class': 'logging.FileHandler',
            'formatter': 'standard'
        }
    },
    'loggers': {
        '': {
            'handlers': ['file_handler'],
            'level': 'INFO',
            'propagate': True
        },
    }
}
logging.config.dictConfig(log_dict)
logging.info("test")

And indeed, it's based on the answer mentioned above

score 5 · Answer 2 · edited Jun 20 '20 at 09:12

5

There are a couple of things wrong with your posted configuration:

A logger with a name of 'root' is not the root logger. The root logger has a name of '' and is in general better configured using a 'root' entry outside the 'loggers' configuration, as described in this part of the logging documentation:

loggers - the corresponding value will be ...

...

root - this will be the configuration for the root logger. ...

You haven't specified a logging level, so it remains at the default level of WARNING, which means that info() messages won't get shown.

edited Jun 20 '20 at 09:12

Community

1
1

answered Apr 22 '16 at 09:33

Vinay Sajip

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While it may be true he has a mistake, I think this misses the point, the question asks for a functional equivalent of [`logging.config.dictConfig(config)`](https://docs.python.org/3/library/logging.config.html#logging.config.dictConfig) for [`logging.basicConfig(**kwargs)`](https://docs.python.org/3/library/logging.html#logging.basicConfig). – tony Jun 04 '22 at 23:16

Basic logging dictConfig in Python

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