Recursive Regex expression to split expression by character

Question

I am looking for a regex expression to split the following type of data:

<exp>(;<exp>)*

and receive a list of every exp but not the delimiter ';'.

So far I have ([^;])(?:;([^;])) but this regex stops at the first exp after ';'. Is there any way to make the lookahead infinite?

Here is a concrete example:

23;hello;2452;ad34aa;bye

I want to get:

[0] = 23
[1] = hello
[2] = 2452
[3] = ad34aa
[4] = bye

I apologize if this question has been answered but I have been unable to find a working expression. If it has please tell me the link.

Thanks for taking the time to read this :)

"Recursive", "lookahead" - these terms are misused in the question. — Wiktor Stribiżew, Apr 22 '16 at 11:32
Just so I do not make a similar mistake again, what words would you suggest to define this problem/question? — user3438286, Apr 28 '16 at 08:30

Nina Scholz · Accepted Answer · 2016-04-22T11:38:16.320

4

Use String#split

var array = '23;hello;2452;ad34aa;bye'.split(';');
document.write('<pre>' + JSON.stringify(array, 0, 4) + '</pre>');

// as mentioned from Avinash Raj
var array2 = '23;hello;2452;ad34aa;bye'.match(/[^;]+/g);
document.write('<pre>' + JSON.stringify(array2, 0, 4) + '</pre>');

edited Apr 22 '16 at 11:38

answered Apr 22 '16 at 11:28

Nina Scholz

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2

also `str.match(/[^;]+/g)` – Avinash Raj Apr 22 '16 at 11:34
1

The String.split assumes the use of javascript language, I was looking for a regex expression, the edition was exactly what I was looking for, thank you. – user3438286 Apr 23 '16 at 11:34

Recursive Regex expression to split expression by character

1 Answers1