Register Container Itself Using Autofac

Question

I was wondering is there's any side effect to registering the container within itself

IContainer container;
ContainerBuilder builder = new ContainerBuilder();
container = builder.Build();
builder.RegisterInstance(container).As<IContainer>();

and the using it like this

builder.RegisterType<IManagmentServiceImp>().As<ManagmentServiceImp>()
    .WithParameter(new ResolvedParameter(
            (pi, ctx) => pi.ParameterType == typeof(IContainer) && pi.Name == "Container",
            (pi, ctx) => container
));

or whether it will even work.

score 43 · Accepted Answer · answered Apr 24 '16 at 14:35

Your code is not safe because you register an instance before it has been initialized.

If you need to have access to the container inside a component (which is not a good idea) you can have a dependency on ILifetimeScope which have Resolve methods.

public class ManagmentServiceImp 
{
    public ManagmentServiceImp(ILifetimeScope scope)
    {
    }
}

ILifetimeScope is automatically registered within Autofac you don't need to add registration for it.

See Controlling Scope and Lifetime from Autofac documentation for more information.

By the way, it is not a good practice to have dependency on your IoC container. It looks like you use Service Locator anti-pattern. If you need the container to lazy load dependency, you can use composition with Func<T> or Lazy<T>

public class ManagmentServiceImp 
{
    public ManagmentServiceImp(Lazy<MyService> myService)
    {
        this._myService = myService; 
    }

    private readonly Lazy<MyService> _myService;
}

In this case, MyService will be created when you first access it.

See Implicit Relationship from the Autofac documentation for more information.

The _trick_ with `Func` & `Lazy` is outstanding! I didn't know Autofac automatically provides them. — t3chb0t, Mar 02 '23 at 20:56
What about a factory that returns one of many different instances? Injecting all of them (with Lazy<>)? — IngoB, Jul 06 '23 at 20:05

score 14 · Answer 2 · edited Aug 15 '20 at 05:32

14

You can use this extension method:

public static void RegisterSelf(this ContainerBuilder builder)
{
    IContainer container = null;
    builder.Register(c => container).AsSelf().SingleInstance();
    builder.RegisterBuildCallback(c => container = c);
}

use it like this: builder.RegisterSelf();

edited Aug 15 '20 at 05:32

Community

1
1

answered Oct 25 '17 at 04:23

torvin

6,515
1
37
52

Using this method i get `The specified CGI application encountered an error and the server terminated the process` after the first request in webapi core and the server is not able to handle requests after that. Changing to ILifetimeScope solved the problem – Adrian Jun 11 '19 at 14:40
1

As of Autofac 5.0, this no longer works - the signature for `.RegisterBuildCallBack()` has changed and now provides an `ILifetimeScope` instead of an `IContainer`. I'm still searching for a workable fix. – Mr. T Feb 05 '20 at 18:24
2

`IContainer` inherits from `ILifetimeScope` so a cast my work... – Matthias Güntert May 28 '20 at 08:32

score 2 · Answer 3 · answered Apr 24 '16 at 04:06

Since you need to provide an instance of the container to builder.RegisterInstance(), you need to initialize it BEFORE passing it as an argument, which you are currently not doing. However, if you structure your container builder to build AFTER registration (and container initialization), you can successfully resolve the container instance in your class.

Please note that this is most certainly a design smell in Dependency Injection and you absolutely should not do this. Your container/kernel should only exist at the top level of your object graph. If you begin injecting your container, you're almost certainly on your way to a Service Locator Anti-Pattern.

void Main()
{
    IContainer container = new ContainerBuilder().Build();
    ContainerBuilder builder = new ContainerBuilder();

    builder.RegisterInstance(container).As<IContainer>();

    builder.RegisterType<ManagementServiceImp>().As<IManagmentServiceImp>()
       .WithParameter(new ResolvedParameter(
            (pi, ctx) => pi.ParameterType == typeof(IContainer) && pi.Name == "Container",
            (pi, ctx) => container
    ));

    container = builder.Build();
    var instance = container.Resolve<IManagmentServiceImp>();
}

public class ManagementServiceImp : IManagmentServiceImp 
{ 
    private IContainer _container;

    public ManagementServiceImp(IContainer Container)
    {
        _container = Container;
        _container.Dump();
    }
}

public interface IManagmentServiceImp { }

@torvin in what way is the container non-configured and in what way does this not solve the OP's need? — David L, Oct 25 '17 at 04:26
sorry I accidentally removed my comment. It was "This is wrong, it will register a non-configured container" — torvin, Oct 25 '17 at 04:27
@torvin you still haven't explained how this fails to meet the OP's needs. — David L, Oct 25 '17 at 04:29
the container will be non-configured in the sense that while you assign the new container `container = builder.Build();` the `builder` will still hold the reference to the previous empty container (created by `new ContainerBuilder().Build()`). You need to use `Register(Func<>)` (see my answer) instead of `RegisterInstance` — torvin, Oct 25 '17 at 04:29

score 1 · Answer 4 · answered Sep 13 '21 at 16:31

1

Try resolving IComponentContext against the container ;)

answered Sep 13 '21 at 16:31

ed22

1,127
2
14
30

Register Container Itself Using Autofac

4 Answers4

Linked