How to read and save an Integer, Double, and String to a variable?

Question

For a online course I'm taking,I'm trying to save the 2nd set of integer, double, and string that I defined to variables, after reading them (the 2nd set) using a scanner. The problem is I don't know how to do that to the 2nd set of variables that I defined. I've tried instantiating them to a new variable,but I keep running into errors. I need help to read each variable and then save them.

 import java.io.*;
 import java.util.*;
 import java.text.*;
 import java.math.*;
 import java.util.regex.*;

 public class Solution {

  public static void main(String[] args) {
    int i = 4;
    double d = 4.0;
    String s = "HackerRank ";


    int j = 4;
    double y = 9.0;
    String k = "is the best place to learn and practice coding!";


    int j = new j();
    double y = new y();
    String k = new k();
    j.scanner.nextInt();
    y.scanner.nextDouble();
    k.scanner.nextLine();


    System.out.print(j + i);
    System.out.print(d + y);
    System.out.print(s + k);

Please share the error message you saw and how do you want variables to be saved. — chinglun, Apr 24 '16 at 07:22
Doesn't your IDE show errors at int j = new j(); double y = new y(); String k = new k();? Because `int j`, `double y` and `String k` are **already defined in the scope**. — Apurva, Apr 24 '16 at 07:22
@Apurva frighteningly a high percentage on SO don't use an IDE :( — Peter Lawrey, Apr 24 '16 at 07:23
I think you need to learn more about how to declare and assign variable in Java — rev_dihazum, Apr 24 '16 at 07:23

score 3 · Answer 1 · answered Apr 24 '16 at 07:22

3

You use assignment without declaring the type again.

int j = 4;
double y = 9.0;
String k = "is the best place to learn and practice coding!";

j = scanner.nextInt();
y = scanner.nextDouble();
k = scanner.nextLine();

answered Apr 24 '16 at 07:22

Peter Lawrey

525,659
79
751
1,130

score 2 · Answer 2 · answered Jun 07 '16 at 22:26

    int j = 12;
    double y = 4.0;
    String k = "is the best place to learn coding!";


    Scanner scanner = new Scanner( System.in );

    j = Integer.parseInt(scanner.nextLine());
    y = Double.parseDouble(scanner.nextLine());
    k = scanner.nextLine();

    //Ensure you print in new line
    System.out.print(j + i);
    System.out.print("\n");
    System.out.print(d + y);
    System.out.print("\n");
    System.out.print(s + k);

score 2 · Accepted Answer · answered Sep 08 '17 at 19:05

A call to nextLine() may return an empty string if there are no characters between the end of the last read and the beginning of the next line.

s1 = scan.nextLine();
s1 = scan.nextLine();

So to complete that challenge use the above code when you read the input from the user. And the entire code goes as follows.

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
int i = 4;
double d = 4.0;
String s = "HackerRank ";

Scanner scan = new Scanner(System.in);
int i1;
double d1;
String s1;

i1 = scan.nextInt();
d1 = scan.nextDouble();
s1 = scan.nextLine();
s1 = scan.nextLine();

System.out.println(i+i1);
System.out.println(d+d1);
System.out.println(s+s1);
scan.close();
}
}

score 0 · Answer 4 · answered Apr 24 '16 at 07:23

All you need to do is the following:

Scanner scanner = new Scanner(System.in);//instantiate a Scanner object

int j = scanner.nextInt();//Use the Scanner object to read an int value from the user
double y = scanner.nextDouble();//Use the Scanner object to read an double value from the user
String k = scanner.nextLine();//Use the Scanner object to read an line  from the user

Lakmal Vithanage · Answer 5 · 2016-04-24T07:29:01.243

     import java.io.*;
     import java.util.*;
     import java.text.*;
     import java.math.*;
     import java.util.regex.*;

     public class Solution {

      public static void main(String[] args) {
        int i = 4;
        double d = 4.0;
        String s = "HackerRank ";


        int j = 4;
        double y = 9.0;
        String k = "is the best place to learn and practice coding!";

Scanner s = new Scanner(System.in);    

        j = Integer.parseInt(s.nextLine());
        y = Double.parseDouble(s.nextLine());
        k = s.nextLine();


        System.out.print(j + i);
        System.out.print(d + y);
        System.out.print(s + k);
}
}

@PeterLawrey , Sorry sir. I missed that. – Lakmal Vithanage Apr 24 '16 at 07:29 — Lakmal Vithanage, Apr 24 '16 at 07:29

score 0 · Answer 6 · answered Jul 22 '16 at 11:44

0

int k = scan.nextInt();
double l = scan.nextDouble();
scan.nextLine();
String f = scan.nextLine();
System.out.println(k + i);
System.out.println(l + d);
System.out.println(s+f);

answered Jul 22 '16 at 11:44

Praveen Narwal

1
1

CdrAshw · Answer 7 · 2016-10-27T00:19:30.683

0

The following code will give you the result

int j;
double y; 
String k=null; 

Scanner scan = new Scanner(System.in);
j= scan.nextInt();
y=scan.nextDouble();

while(scan.hasNext()){
k =scan.nextLine();
}

System.out.println(i+j);
System.out.println(d+y);
System.out.println(s+k);

edited Oct 27 '16 at 00:19

answered Oct 27 '16 at 00:14

CdrAshw

1
1

RavitejaDanda · Answer 8 · 2016-11-13T20:50:24.357

0

            int i1= sc.nextInt();
            double d1 = sc.nextDouble();
            String s1 = sc.next();
            System.out.println(i+i1);
            System.out.println(d+d1);
            System.out.println(s+s1);

you can also follow this if u don't have any spaces for your s1 string.

edited Nov 13 '16 at 20:50

answered Nov 13 '16 at 20:20

RavitejaDanda

19
9

score 0 · Answer 9 · answered Dec 20 '16 at 19:36

import java.io.*;
import java.util.*;
import java.text.*;
import java.math.*;
import java.util.regex.*;

public class Solution {

public static void main(String[] args) {
    int i = 4;
    double d = 4.0;
    String s = "HackerRank ";

    Scanner scan = new Scanner(System.in);


    int j = 4;
    double y = 9.0;
    String k = "is the best place to learn and practice coding!";

    Scanner f = new Scanner(System.in);    

    j = Integer.parseInt(f.nextLine());
    y = Double.parseDouble(f.nextLine());
    k = f.nextLine();


    System.out.println(j + i);
    System.out.println(d + y);
    System.out.println(s + k);


           scan.close();
}

}

While this code snippet may solve the question, [including an explanation](http://meta.stackexchange.com/questions/114762/explaining-entirely-code-based-answers) really helps to improve the quality of your post. Remember that you are answering the question for readers in the future, and those people might not know the reasons for your code suggestion. — DimaSan, Dec 20 '16 at 19:52

How to read and save an Integer, Double, and String to a variable?

9 Answers9