concatenation items as result of one function

Question

I have this function

def one():
    item1 = "one"
    item2 = "two"
    result = item1, item2
    return  result

print(one())

the output of this funciotn is in format tuple, like this

('one', 'two')

What can I do if I need the output not in tuple, so in the following format

one, two

Can someone help? Thanks

replace `result = item1, item2` with `result = item1 + ', ' + item2` — EbraHim, Apr 24 '16 at 10:25

score 1 · Answer 1 · answered Apr 24 '16 at 10:26

1

You can unpack it and specify a custom separator:

print(*one(), sep=', ')

answered Apr 24 '16 at 10:26

TigerhawkT3

score 1 · Accepted Answer · answered Apr 24 '16 at 10:26

1

print(', '.join(one()))

Or in Python 3 you can simply use print() like this:

print(*one(), sep=', ')

which also works in Python 2 if you import print_function like this at the top of your file:

from __future__ import print_function

answered Apr 24 '16 at 10:26

mhawke

How can I call it in a nother funtion? – gho Apr 24 '16 at 10:37
for example: for v, vv in *one(), sep=', ': – gho Apr 24 '16 at 10:39
@gho: If you want a string then use `str.join()` as shown, and then pass that to the second function. e.g. `function2(', '.join(one()))`.Otherwise simply iterate over the returned tuple: `for item in one(): print(item)`. – mhawke Apr 24 '16 at 10:40
I will not make print, I only use it as input for another function – gho Apr 24 '16 at 10:44
@gho: did you read the answer and comments? Use `str.join()`, e.g. `another_function(', '.join(one()))` – mhawke Apr 24 '16 at 10:45
When I call this: for v, vv in ', '.join(one(item)): print(vv), I get this error: TypeError: sequence item 1: expected str instance, set found – gho Apr 24 '16 at 10:49
@gho: why are you doing that? Your function `one()` returns a tuple. You can unpack the tuple into separate variables, if that's what you are hoping to do: `item1, item2 = one()` will set `item1` to the string `one`, and `item2` to `two`. – mhawke Apr 24 '16 at 10:58
With my function I get this error: ValueError: too many values to unpack (expected 2) – gho Apr 24 '16 at 11:02
@gho: then the function that you posted in your question is different from the one that you are testing with. – mhawke Apr 24 '16 at 11:28

score 0 · Answer 3 · answered Apr 24 '16 at 10:25

0

Here you go:

def one():
    item1 = "one"
    item2 = "two"
    result = item1 + ", " + item2
    return  result

print(one())

answered Apr 24 '16 at 10:25

Tamas Hegedus

3 Answers3