string (to binary) to int in python?

Question

I want to make an int from a string in python. I thought to translate the string first to binary like this:

st = 'string'
binSt = ' '.join(format(ord(x), '08b') for x in st)

returns this:

01110011 01110100 01110010 01101001 01101110 01100111

And then I want to translate the binary( in groups of 8) to integers which should to return this:

115 116 114 105 110 103

How can I do this? Is there maybe a special function in python or something?

This is probably what you need: http://stackoverflow.com/a/8928256/5712767 — WreckeR, Apr 26 '16 at 16:22

score 2 · Answer 1 · answered Apr 26 '16 at 16:26

2

You can use the int() function:

result = ''
st = 'string'
binSt = ' '.join(format(ord(x), '08b') for x in st)
binSt_split = binSt.split()
for split in binSt_split:
    result = result + str(int(split,2) + ' '
print result

answered Apr 26 '16 at 16:26

Scratch'N'Purr

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score 2 · Answer 2 · answered Apr 26 '16 at 16:30

2

You can simply do

r = [int(numbs, 2) for numbs in binSt.split(' ')]

int(str, baseNumber) will read the string str and convert it to int using baseNumber

so int("0xFF", 16) = 255 and int("11", 2) = 3

answered Apr 26 '16 at 16:30

Nicolas

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mgilson · Answer 3 · 2016-04-26T16:37:18.773

2

Why not use a bytearray?

>>> barr = bytearray('string')
>>> barr[0]
115

Bytearray does exactly what you want -- It interprets each character in the string as an integer in the range from 0 -> 255.

edited Apr 26 '16 at 16:37

answered Apr 26 '16 at 16:30

mgilson

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score 1 · Accepted Answer · edited May 23 '17 at 10:28

1

Using the solution for binary to int here: Convert base-2 binary number string to int

 binSt = ' '.join([str(int(format(ord(x), '08b'), 2)) for x in st])

And if you just want an array of ints

 int_array = [int(format(ord(x), '08b'), 2) for x in st]

Addressing SpoonMeiser comments. you can avoid intermediate conversions with ord(x)

 int_array = [ord(x) for x in st]

edited May 23 '17 at 10:28

Community

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answered Apr 26 '16 at 16:26

WreckeR

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Having the int -> binary and binary -> int on one line like this seems pointless. If you didn't want the intermediate value (the binary representation) you'd just use `ord(x)` – SpoonMeiser Apr 26 '16 at 16:29
I was answering the OPs question to translate the binary strings to ints. I agree the extra conversions can be avoided. – WreckeR Apr 26 '16 at 16:31
I just mean that it probably a less helpful answer written this way. I think it's implied that the OP actually wanted the binary representation for some reason – SpoonMeiser Apr 26 '16 at 16:36

score 1 · Answer 5 · answered Apr 26 '16 at 16:26

String to binary and then to decimal :

st = 'string'
binSt = ' '.join(format(ord(x), '08b') for x in st)
binSt
##'01110011 01110100 01110010 01101001 01101110 01100111'
bin=binSt.split()
bin
##['01110011', '01110100', '01110010', '01101001', '01101110', '01100111']
print(map(lambda x: int(x,2), bin))
##[115, 116, 114, 105, 110, 103]

## is used for outputs

string (to binary) to int in python?

5 Answers5