Log when extracting 7z archives

Question

I want to create a log file whilst my script extracts 7z

I'm using the following:

7z x "*.7z" >> logfile.log 2>&1

But terminal stops displaying output and the log file is blank...

score 0 · Answer 1 · edited May 23 '17 at 10:33

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Probably the 7z program is detecting that its stdout is not a terminal (TTY), and is choosing not to be so verbose in this case.

Unfortunately, the 7z documentation doesn't seem to offer a "verbose" flag like many programs do. So I'm not sure you can turn the output on easily.

But you can trick the program into thinking it has a terminal on stdout! For example:

script logfile.log 7z x "*.7z"

For more ideas, see: Bash: trick program into thinking stdout is an interactive terminal

edited May 23 '17 at 10:33

Community

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answered Apr 28 '16 at 02:05

John Zwinck

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But wouldn't that log the entire script? I need to just log 7z otherwise the log will be huge, Thanks – NeMesiS Apr 28 '16 at 02:40
@NeMesiS: Try it. It will log the output from 7z. – John Zwinck Apr 28 '16 at 02:44

hd1 · Answer 2 · 2016-04-28T02:46:29.103

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You're redirecting STDERR to STDOUT (that's the 2>&1) and redirecting STDERR to the logfile. Try 7z x "*.7z" 2>&1 > logfile.log. Hope that helps:

% 7z c /tmp/TailsBSDPLIST.7z ~/TailsBSD > /tmp/logfile.log
% cat /tmp/logfile.log
7-Zip (a) 9.38 beta Copyright (c) 1999-2014 Igor Pavlov 2015-01-03 p7zip Version 9.38.1 (locale=C,Utf16=off,HugeFiles=on,1 CPU)

Command Line Error: Unsupported command: c

edited Apr 28 '16 at 02:46

answered Apr 28 '16 at 02:05

hd1

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Thanks but I get the same problem – NeMesiS Apr 28 '16 at 02:37

Log when extracting 7z archives

2 Answers2