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date is in this format %Y-%m-%d %H:%M:%S[this is 24 hours].I want to convert this date in 12 hours something like this -> %Y-%m-%d %H:%M:%S %p and vice-versa. How can i achieve this?? Thanx!

Pranay
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2 Answers2

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Load the string into a datetime object via strptime(), then dump via strftime() in the desired format:

>>> from datetime import datetime
>>> d = datetime.now().strftime("%Y-%m-%d %H:%M:%S")
>>> d  # d is a string
'2016-04-28 07:46:32'
>>> datetime.strptime(d, "%Y-%m-%d %H:%M:%S").strftime("%Y-%m-%d %I:%M:%S %p")
'2016-04-28 07:46:32 AM'

Note that the %I here is a 12-hour clock.

alecxe
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  • Thank you ! @alecxe..and vice-versa..I mean again wanted to 24 of 12 hours then??? – Pranay Apr 28 '16 at 11:52
  • @Pranay make the same procedure, but now `strptime` using `%Y-%m-%d %I:%M:%S %p` and `strftime` using `%Y-%m-%d %H:%M:%S`. – alecxe Apr 28 '16 at 11:53
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24 hour to 12-hour

>>> from datetime import datetime
>>> datetime.strptime('2016-05-25 13:45:56', '%Y-%m-%d %H:%M:%S')
datetime.datetime(2016, 5, 25, 13, 45, 56)
>>> dt=datetime.strptime('2016-05-25 13:45:56', '%Y-%m-%d %H:%M:%S')
>>> dt.strftime('%Y-%m-%d %I:%M:%S %p')
'2016-05-25 01:45:56 PM'
>>>

12-hour to 24-hour

>>> dt=datetime.strptime('2016-05-25 01:45:56 PM', '%Y-%m-%d %I:%M:%S %p')
>>> dt
datetime.datetime(2016, 5, 25, 13, 45, 56)
>>> dt.strftime('%Y-%m-%d %H:%M:%S')
'2016-05-25 13:45:56'
>>>
riteshtch
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