sort
only really works "out-of-the-box" when sorting character data alphabetically. And why would you expect it to call your functions and compare them? That's really dangerous and complicated. However, you can perform your own special sort by passing it a function.
Taken from the docs (compareFunction
is the function you're passing in):
If compareFunction
is supplied, the array elements are sorted according to the return value of the compare function. If a and b are two elements being compared, then:
If compareFunction(a, b)
is less than 0, sort a to a lower index than b, i.e. a comes first.
If compareFunction(a, b)
returns 0, leave a and b unchanged with respect to each other, but sorted with respect to all different elements. Note: the ECMAscript standard does not guarantee this behaviour, and thus not all browsers (e.g. Mozilla versions dating back to at least 2003) respect this.
If compareFunction(a, b)
is greater than 0, sort b to a lower index than a.
compareFunction(a, b)
must always return the same value when given a specific pair of elements a and b as its two arguments. If inconsistent results are returned then the sort order is undefined.
arr.sort(function(a, b) {
// localeCompare does a string comparison that returns -1, 0, or 1
return a.elem.text().localeCompare(b.elem.text());
});