In Batch variable not printing

Question

I am writing a batch file to kill all the dependent process for given process ID.I have not completed my code yet.For now my code is

set cmd="wmic process where (ParentProcessId=4192) get ProcessId"
FOR /F %%i IN (' %cmd% ') DO ( 
SET X=%%i 
echo The process is %X%
)

The output of "wmic process where (ParentProcessId=4192) get ProcessId" command is :

ProcessID
3516
<blank space>

In batch it is setting X=ProcessID,3516 and blank space. problem 1: for above code it is not displaying the value of X (in echo). Problem 2: I want those %%i which is integer

[delayed expansion](http://ss64.com/nt/delayedexpansion.html) — npocmaka, May 01 '16 at 15:15
And in this example, you don't even need to set `%X%`; just echo `%%i` — SomethingDark, May 01 '16 at 17:15
Possible duplicate of [Batch file variables initialized in a for loop](http://stackoverflow.com/questions/691047/batch-file-variables-initialized-in-a-for-loop) — Mofi, May 01 '16 at 18:00

Hackoo · Answer 1 · 2016-05-02T09:11:43.037

You can try something like that :

@echo off
set cmd="wmic process where (ProcessId=4192) get ParentProcessId"
Setlocal EnableDelayedExpansion
FOR /F "skip=1 delims=" %%i IN ('%cmd%') DO ( 
    SET X=%%i 
    echo The process is !X!
)
pause
echo The process is %X%
EndLocal
pause

And why you don't use Taskkill command with param /T to terminates the specified process and any child processes which were started by it ?

In Batch variable not printing

1 Answers1