I want to implement Unix milliseconds converter to human readable date format. using this post https://stackoverflow.com/a/1657307/1979882 I found I can receive such string but I can't setup a time zone inside the code. The code uses only system time zone.
#include <stdio.h>
#include <time.h>
int main ( int argc, char *argv[] )
{
time_t now;
struct tm *lcltime;
now = time ( NULL );
lcltime = localtime ( &now );
printf ( "The time is %d:%d\n", lcltime->tm_hour, lcltime->tm_min );
return 0;
}
Is it possible to customize it?
EDIT
I need some Java-like method:
SimpleDateFormat df= new SimpleDateFormat("dd MMM hh:mm z",Locale.ENGLISH);
df.setTimeZone("Europe/London");
System.out.println("London Time " + df.format(System.currentTime()));
df.setTimeZone("Asia/Benjin");
System.out.println("Benjin Time " + df.format(System.currentTime()));
EDIT_2
I found I can setup time zone using setenv(...) url https://stackoverflow.com/a/1620451/1979882
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
int main (int argc, char *argv[])
{
struct tm *mt;
time_t mtt;
char ftime[10];
setenv("TZ", "PST8PDT", 1);
tzset();
mtt = time(NULL);
mt = localtime(&mtt);
strftime(ftime,sizeof(ftime),"%Z %H%M",mt);
printf("%s\n", ftime);
}
But in changes the system time zone. I need just time zone modification only inside my code.