Php explode string only if the string contains '.'

Question

I have this explode (with list):

$dm = "blablabla.ff";
list($d, $l) = explode('.', $dm, 2);

Now, i want the explode will cut the string only if the string contains . because the list will return error if the string not contains ., error like this: Undefined offset: 1.

How can i do this short way?

Possible duplicate of [Check if string contains specific words?](http://stackoverflow.com/questions/4366730/check-if-string-contains-specific-words) — Federkun, May 02 '16 at 21:33
@Federico No, in addition i search solution for the `Undefined offset: 1` problem. — , May 02 '16 at 21:34
this is not a good approach if your wanting a filename extension (which it kind of looks like) — , May 02 '16 at 21:35
Possible duplicate of [Getting domain extension from URL?](http://stackoverflow.com/questions/17487559/getting-domain-extension-from-url) — chris85, May 02 '16 at 21:44

score 2 · Accepted Answer · answered May 02 '16 at 21:42

2

$dm = "blablabla.ff";
if(strpos($dm,".") !== false){
    list($d, $l) = explode('.', $dm, 2);
}

answered May 02 '16 at 21:42

aprogrammer

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score 0 · Answer 2 · answered May 02 '16 at 21:49

If you explode $dm = "blablabla.ff"; you get two arrays. one for $d and one for $l.

$d = 'blablabla';
$l = 'ff';

If you explode $dm = "blablablaff"; you get one array. One for $d and no one for $l.

$d = 'blablablaff';
$l = null;

Now if you have no arrays to fill the list ($l) it will error.

score 0 · Answer 3 · answered May 02 '16 at 21:52

0

You could try this:

    <?php
        $dm     = "blablabla.ff";
        $d      = null;
        $l      = null;

        if( stristr($dm, ".")){
            list($d, $l) = explode('.', $dm, 2);
        }       

        var_dump($d, $l);

answered May 02 '16 at 21:52

Poiz

7,611
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Php explode string only if the string contains '.'

3 Answers3