convert from list to json in java

Question

I have a list and I want to convert it to json.

Here is my code

JqGridModel gridModel1 = new JqGridModel();
Date FromDate = new Date("1996-07-04");
Date ToDate = new Date("1996-07-05");
gridModel1.setOrderID(10248);
gridModel1.setFromDate(FromDate);
gridModel1.setToDate(ToDate);
gridModel1.setCustomerID("WILMK");
gridModel1.setShipName("Vins et alcools Chevalier");

JqGridModel gridModel2 = new JqGridModel();
Date FromDate2 = new Date("1996-07-04");
Date ToDate2 = new Date("1996-07-05");
gridModel2.setOrderID(10248);
gridModel2.setFromDate(FromDate2);
gridModel2.setToDate(ToDate2);
gridModel2.setCustomerID("WILMK");
gridModel2.setShipName("Vins et alcools Chevalier");



List jqGridModels = new ArrayList();
jqGridModels.add(gridModel1);
jqGridModels.add(gridModel2);

And I want to convert it to be in the following format:

{ 
    "rows":[
        {"OrderID":"10248","FromDate":"1996-07-04","CustomerID":"WILMK","ShipName":"Vins et alcools Chevalier","ToDate":"1996-07-05"},
        {"OrderID":"10249","FromDate":"1996-07-05","CustomerID":"TRADH","ShipName":"Toms Spezialit\u00e4ten","ToDate":"1996-07-17"},
        {"OrderID":"10250","FromDate":"1996-07-08","CustomerID":"HANAR","ShipName":"Hanari Carnes","ToDate":"1996-07-26"},
        {"OrderID":"10251","FromDate":"1996-07-08","CustomerID":"VICTE","ShipName":"Victuailles en stock","ToDate":"1996-08-01"},
        {"OrderID":"10252","FromDate":"1996-07-09","CustomerID":"SUPRD","ShipName":"Supr\u00eames d\u00e9lices","ToDate":"1996-08-01"}
    ]
}

Any help would be greatly appreciated.

Possible duplicate of [How to convert List to Json in Java](http://stackoverflow.com/questions/14228912/how-to-convert-list-to-json-in-java) — Jonny Henly, May 03 '16 at 07:45
try this >> https://stackoverflow.com/questions/14228912/how-to-convert-list-to-json-in-java — Vikrant Kashyap, May 03 '16 at 07:50
Did you know that you linked to the question that I proposed was a possible duplicate? : ) @VikrantKashyap — Jonny Henly, May 03 '16 at 08:06

Lorenzo Barbagli · Answer 1 · 2016-05-03T08:44:24.517

Firstly: use generics

List jqGridModels = new ArrayList();  //bad
List<JqGridModel> jqGridModels = new ArrayList<>();  //good

Secondly: Can you use Gson?

List<JqGridModel> jqGridModels = new ArrayList<>();

Gson gson = new Gson();
JsonElement jsElem = gson.toJsonTree(jqGridModels, new TypeToken<List<JqGridModel>>() {}.getType());

if (! jsElem.isJsonArray()) {
    //this is an error...
}

JsonArray jsonArray = jsElem.getAsJsonArray();

Haven't tested it yet but it should work, I'm doing this in my project and it's ok, if you have more troubles please tell me!

score 1 · Answer 2 · answered May 03 '16 at 07:51

If you want to do it manually you can :

Create a method to generate the JSON from tour object :

class JqGridModel{

    public JSONObject toJSON(){
        JSONObject json = new JSONObject();
        json.accumulate("OrderID", orderID);
        // DO the same for all attributes
        return  json;
    }
}

And then call this method looping on the list content :

JSONObject json = new JSONObject();
JSONArray arr = new JSONArray();
for(JqGridModel m: jqGridModels){
     arr.put(m.toJSON());
}
json.accumulate("rows", arr);

score 0 · Answer 3 · answered May 03 '16 at 08:28

    com.fasterxml.jackson.databind.ObjectMapper mapper = new com.fasterxml.jackson.databind.ObjectMapper();
    StringBuffer result = new StringBuffer("{\n\t\"rows\":[\n");
    try {
        for(Object item : jqGridModels){
            result = result.append("\t\t\t");
            result = result.append(mapper.writeValueAsString(item));
            result = result.append("\n");
        }
        if(jqGridModels.size() > 1){
            result = result.append("\t]\n}");
            System.out.print(result);
        }
    } catch (JsonProcessingException e) {
        e.printStackTrace();
    }

convert from list to json in java

3 Answers3