Django Admin Custom Widget for ForeignKey

Question

It sounds like a trivial question, but it seems not so easy to answer:

How would you display a ForeignKey field as a Checkbox in Django Admin and save the currently logged in user whenever this user checks the checkbox in Admin?

Example:

class MyModel(models.Model):
    ...
    approved = models.ForeignKey(User)
    ...

admin.site.register(MyModel)

How would I be able to display the approved field as a checkbox?

Thanks alot in advance for your help!

score 0 · Answer 1 · answered May 04 '16 at 08:05

0

You could use the get_form method on your ModelAdmin, and customize the form to what you wish.

In this case, you would have to change the fields widget to a checkbox, and set the value to request.user on form validation (if checked).

answered May 04 '16 at 08:05

Alvin Lindstam

3,094
16
28

Thanks for your answer! And you are sure Django's form cleaning methods dont block this approach? – Matthias Scholz May 04 '16 at 08:07
Since you would have to implement the clean method for this field, it's all up to you. Not Django. – Alvin Lindstam May 04 '16 at 08:20

score 0 · Answer 2 · answered May 04 '16 at 08:08

You can customize it as follows in admin.py

class MyModelWidget(forms.ModelForm):
    approved = forms.BooleanField(widget=forms.CheckboxInput())

    class Meta:
        model = MyModel
admin.site.register(MyModel, MyModelWidget)

Refer https://docs.djangoproject.com/en/1.9/ref/contrib/admin/

score 0 · Answer 3 · answered May 04 '16 at 08:11

0

In your form.py:

class YOURMODELForm(forms.ModelForm):
    approved = forms.ModelChoiceField(queryset=User.objects.order_by('name'))

answered May 04 '16 at 08:11

Ohad the Lad

1,889
1
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Django Admin Custom Widget for ForeignKey

3 Answers3