javascript Regular Expressions

Question

I have the following url

http://www.test.info/?id=50&size=40

How do I get the value of the url parameter with regular expressions in javascript . i need the size value and also need the url without &?

only

http://www.test.info/?id=50

Thanks

Answer 1

Just use this as your regex

size.*?(?=&|$)

here is some code you can use

var re = /size.*?(?=&|$)/g;
var myArray = url.match(re);
console.log(myArray);

you also can do it like this:

var re = new RegExp("size.*?(?=&|$)", "g");

Answer 2

Here is a regex pattern you could use.

^(.+)&size=(\d+)

The first group will be the url up to right before the '&' sign. The second group will be the value of the size parameter. This assumes id always comes before size, and that there are only two parameters: id and size.

Answer 3

Consider using split instead of a regex:

var splitted = 'http://www.test.info/?id=50&size=40'.split('&');
var urlWithoutAmpersand = splitted[0];
// now urlWithoutAmpersand => 'http://www.test.info/?id=50'
var sizeValue = splitted[1].split('=')[1] * 1;
// now sizeValue => 40