Count values of dictionary

Question

I'm having a problem here, its counting the empty lists which must not be counted

Is there a way to not count the empty lists?

dic ={None: [[], [], [(3, 2, 0)], [(3, 1, 0)], [], [], [(4, 3, 2), (4, 3, 0)], [(4, 2, 0)]]}
x = list(map(len, dic.values()))
print(x[0])

Output Required

My code Outpute

In you're example I see 4 none empty list and not 5. – ar-ms May 07 '16 at 15:23 — ar-ms, May 07 '16 at 15:23

score 3 · Accepted Answer · edited May 23 '17 at 11:59

3

dic.values() wraps all the values from different keys inside another list:

>>> dic.values()
[[[], [], [(3, 2, 0)], [(3, 1, 0)], [], [], [(4, 3, 2), (4, 3, 0)], [(4, 2, 0)]]]

Since, you have only one key there is only one element in dic.values() and when you do x = list(map(len, dic.values())) you get 8 because that's the length on the inner list.

You need to iterate over the inner list dic.values()[0] and get the length from there:

>>> sum(map(len, dic.values()[0]))
5

UPDATE: If you are using python 3, you can get the first value as list(dic.values())[0]:

>>> sum(map(len, list(dic.values())[0]))
5

This SO Post list many ways you can get the first value.

edited May 23 '17 at 11:59

Community

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answered May 07 '16 at 15:02

AKS

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I'm getting an error TypeError: 'dict_values' object does not support indexing – jack May 07 '16 at 15:25
It seems you are using python3. Please try `list(dic.values())[0]` – AKS May 07 '16 at 15:27

Count values of dictionary

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