Entery code.. Error:entery.exe stopped working. C language

Question

this code is supposed to get username and password entered.. username is Admin and password is 2016.. if the user enters them correctly it'll print that the login process was done successfully else it'll ask the user to enter them again.. I made the code but it's not working and I don't know why.. here it's:

#include <stdio.h>
int main(){
    char* *username[5]; int password,choice; char Admin,i;

    printf("Welcome to the Students' Registration System\n");
    printf("Dear Registry employee: Kindly insert your username:\n");
    for (i=0;i<5;i++){
        scanf("%c", &username[i]);  
    }
    printf("Insert your password:\n");
    scanf("%d", &password);


    if ((*username[5]=="Admin")&&(password==2016))
    printf("The login process is successfully done");
    else 
    while ((*username[5]!="Admin")||(password!=2016))
   {
        printf("The login process failed\n");
        printf("Dear Registry employee: Kindly insert the correct username and password\n");
        for (i=0;i<5;i++){
            scanf("%c", &username[i]);
        }
        scanf("%d", &password); 
    }

    printf("Please choose the number of your next step:\n");
    printf("[1]Add new student\n");
    printf("[2]Add new course\n");
    printf("[3]Assign\remove courses for the student\n");
    printf("[4]Search and view students' details:\n");
    printf("[5]Request reports:\n"); 
    printf("[6]Update student/course record:\n");
    printf("[7]Delete student/course record:\n");

    return 0;
 }

Answer 1

There are multiple issues with your program, which includes:

• Delcaration of username as array of pointers pointing to character pointers
• Length of username is not sufficient enough to hold default password admin
• Reading username using a loop.
• Comparing string using == and != operator.

A better approach can be as follows.

#include <stdio.h>
#include <string.h>

int main()
{
    //Admin has 5 characters, and string requires one null terminator. So minimum length should be 6
    char username[10]; 
    int password,choice; 
    char Admin,i;

    printf("Welcome to the Students' Registration System\n");


    do
    {
        printf("Dear Registry employee: Kindly insert your username:\n");
        //Use %s to read a string completely(till white space character)
        scanf("%s", username);
        printf("Insert your password:\n");
        scanf("%d", &password);


        //You can't compare string using == or !=
    }while (strcmp(username, "admin") != 0 && password != 2016 );

    printf("The login process is successfully done");

    printf("Please choose the number of your next step:\n");
    printf("[1]Add new student\n");
    printf("[2]Add new course\n");
    printf("[3]Assign\remove courses for the student\n");
    printf("[4]Search and view students' details:\n");
    printf("[5]Request reports:\n"); 
    printf("[6]Update student/course record:\n");
    printf("[7]Delete student/course record:\n");

    return 0;
}

Answer 2

How to read / parse input in C? The FAQ.. Start at the section "Do not use *scanf() for potentially malformed input", and read on from there.

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I don't give ready-to-use answers to homework questions, but some hints on your particular problem:

char* *username[5]

This is an array of 5 pointers to pointers to char. Not what you want, really. You want an array of characters, a.k.a. a "string".

for (i=0;i<5;i++){
        scanf("%c", &username[i]);  
    }

This (%c) reads one character at a time. Again, you want a string. You could do that with scanf( "%s", ... ), but you really should not do that. You want fgets().

if ((*username[5]=="Admin")&&(password==2016))

username[5]? After you read one character at a time? You see the problem?

There is a function named strncmp that you might be interested in.