How to check edittext

Question

I want to add a verification to my edit text:

check if the name is not a number
check if the tel is a number
check if the password and password2 are equals

How can I do this?

if (name.isEmpty() || name.length() < 3 ||  ............) {
     et_name.setError("enter a valid name");
     valid = false;
} else {
     et_nom.setError(null);
}
if (tel.isEmpty() || ..........) {
     et_tel.setError("enter a valid tel");
     valid = false;
} else {
     et_tel.setError(null);
}
if (password.isEmpty() || password2.isEmpty() || ..........) {
     et_password.setError("enter a valid password");
     valid = false;
} else {
     et_password.setError(null);
}

Why not just set the `inputType="number"` of the `editText` in the xml? — AL., May 10 '16 at 07:39

score 2 · Answer 1 · answered May 10 '16 at 08:12

Okey...

first :

for name you don't want allow user to enter numbers so what you can do is add two attributes to your name EditText.

android:digits="abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ "
android:inputType="text"

This will allow user to enter only alphabets and blank space. so no need for verification on that programmatically.

Second :

Same for the telephone number. you have to add android:inputType="number" to your telephone EditText. So user will able to input numbers only.

Third

for validating if your EditText is empty or not you can do following.

if (name.getText().toString().equals("")) {
    Toast.makeText(getApplicationContext(),
                    "Please enter your name", Toast.LENGTH_SHORT).show();
}

Fourth

For checking password equality you can do following.

if (!password1.getText().toString().equals(password2.getText().toString())) {
    Toast.makeText(getApplicationContext(),
                    "Please enter your name", Toast.LENGTH_SHORT).show();
}

Now Hopefully you understand this whole process. for your case refer following code.

if (name.getText().toString().equals("") || name.length() < 3 ||) {
        et_name.setError("enter a valid name");
        valid = false;
} 
if (tel.getText().toString().equals("")) {
        et_tel.setError("enter a valid tel");
        valid = false;
} 
if (password.getText().toString().equals("") || password2.getText().toString().equals("") || !password.getText().toString().equals(password2.getText().toString())) {
        et_password.setError("enter a valid password");
        valid = false;
}

Happy coding.

score 1 · Answer 2 · edited May 23 '17 at 10:29

1

Why not just set the inputType="number" of the EditText in the xml? If you still prefer checking it dynamically, check out this post.
TextUtils.equals() - http://developer.android.com/reference/android/text/TextUtils.html#equals(java.lang.CharSequence, java.lang.CharSequence)

Cheers! :D

edited May 23 '17 at 10:29

Community

1
1

answered May 10 '16 at 07:41

AL.

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score 0 · Answer 3 · edited Jun 06 '16 at 13:37

Try using android.text.Utils.TextUtils class (part of android SDK)

See inputType

1. Check if name is number

if(TextUtils.isDigitsOnly(str)) {
  //number
}

2. Check if name is not a number

if(!TextUtils.isDigitsOnly(str)) {
  //number
}

3. Check if two password1 and password2 are equal

if(!TextUtils.isEmpty(password1) && !TextUtils.isEmpty(password2) && !password1.equals(password2)) {
  //number
}

How to check edittext

3 Answers3