Multiple bit manipulation in python

Question

I have a variable containing a value in bit, ex 10000000 representing 10mb. I'd like to write a function that from a value in bit, return a string with the right unit and correctly converted.

Example if I use 52200000, it returns 52.2mb.

I don't know how to proceed. Can someone help, thank you

This formats bytes to human readable: http://stackoverflow.com/questions/1094841/reusable-library-to-get-human-readable-version-of-file-size — Schore, May 10 '16 at 10:40

score 1 · Accepted Answer · answered May 10 '16 at 10:57

1

def humanize(n):
   base=1000.0   # replace with 1024 if you want kib Mib etc
   letters=['','k','M','G','T','P','E','Z','Y'] 
   f=float(n)
   for x in letters:
       if f < base: break
       f /= base
   return '{:.3}{}b'.format(f,x) # change {}b to {}ib if working with kib etc.

These days Mb normally refers to a decimal million bytes and Mib normally refers to 1024*1024 of them. This code is trivial to switch.

answered May 10 '16 at 10:57

nigel222

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Mb refers to Million *Bits*, MB is Million *Bytes* – SiHa May 10 '16 at 12:24

Himanshu dua · Answer 2 · 2016-05-10T11:06:13.760

0

def bytesto(bytes, to, bsize=1000):
    a = {'k' : 1, 'm': 2, 'g' : 3, 't' : 4, 'p' : 5, 'e' : 6 }
    r = float(bytes)
    for i in range(a[to]):
        r = r / bsize
    return(r)

you can use above function to convert bytes to kb,mb,gb,tb

Convert bytes to KB print(bytesto(314575262000000, 'k')) # 314575262000.0 KB
Convert bytes to MB print(bytesto(314575262000000, 'm')) # 314575262.0 MB
Convert bytes to TB print(bytesto(314575262000000, 't')) # 314.575262 TB

edited May 10 '16 at 11:06

answered May 10 '16 at 10:41

Himanshu dua

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You're confusing MB (=1000B) and MiB (=1024B) - see: https://en.wikipedia.org/wiki/Binary_prefix – mata May 10 '16 at 11:01
@mata Got IT the difference between MIB and MB. Thanks – Himanshu dua May 10 '16 at 11:04

Multiple bit manipulation in python

2 Answers2