I use the following in gulp
to build a CSS file from a SASS (*.scss) file :
var gulp = require('gulp')
, sass = require('gulp-sass');
var colortheme = 'blue';
gulp.task('build_css', function() {
return gulp.src(['resources/assets/sass/app/' + colortheme + '.scss'])
.pipe(sass())
.pipe(gulp.dest('public/css/'));
} );
As you can see I use a different .scss file for each colortheme.
I would like to use only one .scss file but be able to pass the colortheme somehow as a parameter, so this can be used as a variable inside the .scss file.
Is this possible?