Generating dates in PHP

Question

Here's my code:

$d = new DateTime('2016-07-14');
$inc = new DateInterval('P1D');
$dateOptions = '';
//1=monday 2=tuesday 3=wednesday
$required = array(1,2,3,4);
$counter = $week = 0;
for ($i=0; $i<40; ++$i){
    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % 4 == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

Here's the output:

1
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
2
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

The output I would like looks like this:

1
Thursday, July 14, 2016
2
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
3
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

What changes to the code needs to be made to allow Thursday to output in the first week?

Thanks in advance!

take help from [php-datetime-class-change-first-day-of-the-week-to-monday](http://stackoverflow.com/questions/13128854/php-datetime-class-change-first-day-of-the-week-to-monday) — Murad Hasan, May 12 '16 at 06:23

score 1 · Answer 1 · answered May 12 '16 at 06:49

You are incrementing the counter which gets initialized from 0. So change to week number
You are asking to start from given date, but incrementing it inside the loop. So subtract it before the loop

So your modified code:

<?php
$d = new DateTime('2016-07-14');
$inc = new DateInterval('P1D');

$d = $d->sub($inc); // You need the start date from 14

$required = array(1,2,3,4);
$week = 0;
for ($i=0; $i<40; ++$i){
    $d = $d->add($inc);
    $weekNumber = $d->format('w');
    if (in_array($weekNumber, $required)) {
        if(!($weekNumber-1) % 4){   //Don't calculate the counter, but the week number
            echo (++$week) . "<br />";
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
    }
}

Output:

Thursday, July 14, 2016
1
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
2
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016
3
Monday, August 01, 2016
Tuesday, August 02, 2016
Wednesday, August 03, 2016
Thursday, August 04, 2016
4
Monday, August 08, 2016
Tuesday, August 09, 2016
Wednesday, August 10, 2016
Thursday, August 11, 2016
5
Monday, August 15, 2016
Tuesday, August 16, 2016
Wednesday, August 17, 2016
Thursday, August 18, 2016
6
Monday, August 22, 2016

Your Eval

@TimM Welcome. Don't forget to accept if it answered your query — Thamilhan, May 13 '16 at 00:35

score 0 · Accepted Answer · answered May 12 '16 at 06:27

0

Use below code,

for ($i=0; $i<40; ++$i){
    if($i==0)
    {
        echo ($week + 1) . "<br />";
            ++$week;
    $t = $d->format('l, F d, Y');
        echo $t . "<br />";  

    }
    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % 4 == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }
        $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

Output:

1
Thursday, July 14, 2016
2
Monday, July 18, 2016
Tuesday, July 19, 2016
Wednesday, July 20, 2016
Thursday, July 21, 2016
3
Monday, July 25, 2016
Tuesday, July 26, 2016
Wednesday, July 27, 2016
Thursday, July 28, 2016

answered May 12 '16 at 06:27

Brijal Savaliya

1,101
9
19

Why should OP "use this code"? What do you changed and why? – Rizier123 May 12 '16 at 06:29
he has done, "$inc = new DateInterval('P1D');" which increments one day ,so if he wants to fetch current date also he can get it by above code, just logincally changes to his code @Rizier123 – Brijal Savaliya May 12 '16 at 06:31
@TimM if its helpful to you then please UV and accept answer – Brijal Savaliya May 13 '16 at 03:45

score 0 · Answer 3 · answered May 14 '16 at 20:37

Here's the final code I used:

$d = new DateTime('2016-08-29');
$inc = new DateInterval('P1D');

$d = $d->sub($inc); 

$required = array(2,4); //1=monday 2=tuesday 3=wednesday 4=thursday 5=friday
$howmany = count($required);

$week = 0;

for ($i=0; $i<120; ++$i){

    $d = $d->add($inc);
    if (in_array($d->format('w'), $required)) {
        if($counter % $howmany == 0){
            echo ($week + 1) . "<br />";
            ++$week;
        }

    $t = $d->format('l, F d, Y');
        echo $t . "<br />";   
        ++$counter;
    }
}

Thanks for the help!

Generating dates in PHP

3 Answers3