Mapping user space to physical memory

Asked May 12 '16 at 10:51

Active May 12 '16 at 10:51

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I know that there are three zones in physical memory:

ZONE_DMA - Contains page frames of memory below 16 MB
ZONE_NORMAL - Contains page frames of memory at and above 16 MB and below 896 MB
ZONE_HIGHMEM - Contains page frames of memory at and above 896 MB

But i'm wondering that where is the user-space(3G) exist on these zones? And how to map user-space to physical memory? Please help me understand.

asked May 12 '16 at 10:51

Tiktac

As for your first question, "anywhere". Because that's how MMUs work. – Ignacio Vazquez-Abrams May 12 '16 at 11:00
As far as i know, kernel space will be mapped from 0-896MB area, which is corresponding to ZONE_DMA and ZONE_NORMAL, so user space is mapped to ZONE_HIGH? – Tiktac May 12 '16 at 11:10
Can someone tell me how this is a duplicate of the one linked? The answer there does not even begins to address this question. – user3344003 May 12 '16 at 19:47

Mapping user space to physical memory

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