RegEx select url and strip a part

Question

I have this:

<li><a href="/page.asp?dac=all&amp;num=266">Company Name</a></li>

Using the following RegEx I could grab the url part:

(?<=<li><a href=").*num=.*(?=">)

I want to get the url without "amp;" section. So the result would be like:

/page.asp?dac=all&num=266

How should I do that?

Then you need som kind of code. What environment are we talking about? Language, Editor... (You'll have to use capture groups) — SamWhan, May 12 '16 at 14:15
I using a Bot maker software. ZennoPoster, if it's not against rules here. — Mehdi, May 12 '16 at 14:20
I guess what you really want to do is decode the string. I.e. Convert the `&` entity to `&`. — SamWhan, May 12 '16 at 14:20
Can ZennoPoster use capture groups in the regex? If so, you could use that and output \1 and \2. For example :

score 0 · Answer 1 · answered May 12 '16 at 14:46

You should be able to do that using regex replace.

For C# it can look like the following:

var input = "<li><a href="/page.asp?dac=all&amp;num=266">Company Name</a></li>";
var pattern = ".*<a href="(?<before>.*)&amp;(?<after>.*)">.*";
var replace = "${before}&${after}";
var result = Regex.Replace(input, pattern, replace);

Hermes Martinez · Answer 2 · 2016-05-12T14:58:15.500

0

I think what you want is just:

s/(?<=<li><a href=".*)(?:amp;)(.*)/$1$2/

then <li><a href="/page.asp?dac=all&num=266">Company Name</a></li>

becomes <li><a href="/page.asp?dac=all&num=266">Company Name</a></li>

edited May 12 '16 at 14:58

answered May 12 '16 at 14:47

Hermes Martinez

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RegEx select url and strip a part

2 Answers2