Unknown modifier '/' error in PHP

Question

preg_replace('/http:///ftp:///', 'https://', $value);

http:// and ftp:// inside $value should be replaced with https://

This code gives error:

preg_replace() [function.preg-replace]: Unknown modifier '/' 

What is a true regex for this task?

Answer 1

Try using a different delimiter, say #:

preg_replace('#http://|ftp://#', 'https://', $value);

or (less recommended) escape every occurrence of the delimiter in the regex:

preg_replace('/http:\/\/|ftp:\/\//', 'https://', $value);

Also you are searching for the pattern http:///ftp:// which really does not make much sense, may be you meant http://|ftp://.

You can make your regex shorter as:

preg_replace('#(?:http|ftp)#', 'https', $value);

Understanding the error: Unknown modifier '/'

In your regex '/http:///ftp:///', the first / is considered as starting delimiter and the / after the : is considered as the ending delimiter. Now we know we can provide modifier to the regex to alter its default behavior. Some such modifiers are:

• i : to make the matching case insensitive
• m : multi-line searching

But what PHP sees after the closing delimiter is another / and tries to interpret it as a modifier but fails, resulting in the error.

preg_replace returns the altered string.

$value = 'http://foo.com';
$value = preg_replace('#http://|ftp://#', 'https://', $value);
// $value is now https://foo.com

Answer 2

Use another delimiter character, like '#', for instance.

preg_replace('#/http://|ftp://#', 'https://', $value);

And do not confuse / and |

Answer 3

preg_replace('!(http://|ftp://)!', 'https://', $value);

Long story: Regexp needs to be enclosed in delimiters, and those have to be unique inside the whole regexp. If you want to use /, then the remaining /-s inside the regexp need to be escaped. This however makes the syntax look a bit ugly. Luckily you can use any character as delimiter. ! works fine, as will other characters.

The rest of the regexp just lists two options, either of which will be replaced with the second parameter.

Answer 4

preg_replace('|http:\/\/ftp:\/\/', 'https://|', $value);

Answer 5

Use this instead:

preg_replace('-(http|ftp)://-', 'https://', $value);

Or

preg_replace('/(http|ftp):\/\//', 'https://', $value);