javascript validation and ajax call simultaneously not working

Question

I have code in that javascript and ajax call need to be work simultaneously. But it did not work. And always go to return true.

Functionality of create function is validation of data and ajax call which execute query and depend on result it will further execute. If response text is yes then it call confirmval function. And then further it ask for confirmation and next execution But I face problem is function not return false it always go to true. I cant understand why this happening?

function create()
            {                        
                if (document.companyregister.cmpname.value === "")
                {
                    alert("Please Enter Company name");
                    document.companyregister.cmpname.value = "";
                    document.companyregister.cmpname.focus();
                    return false;
                }

                var companyname = document.companyregister.cmpname.value;
                var username = document.companyregister.username.value;
                    $.ajax({
                    url: 'checkexisting.php',
                    type: 'POST',
                    data: {companyname: companyname,username:username},
                    success: function(errorResponse) {
                        var result = errorResponse.trim();                        
                        if(result=="yes"){                            
                            return confirmval(companyname,username);                                
                        }
                        else{
                            document.getElementById("formsubmitting").style.display = "block";
                            document.getElementById("hidesubmit").style.display = "none";
                            return true;
                        }                        
                        }
                    });
}

function confirmval(companyname,username){
                var c = confirm("This company is already created.\nWould you like to delete existing company?");                
                if(c){  
                    alert("c");                    
                    $.ajax({
                    url: 'updatecompany.php',
                    type: 'POST',
                    data: {companyname: companyname,username:username},
                    success: function(responsetext) {
                        var result = responsetext.trim();                        
                        if(result=="yes"){
                            document.getElementById("formsubmitting").style.display = "block";
                            document.getElementById("hidesubmit").style.display = "none";
                            return true;
                        }                                            
                        }
                    });
                }
                else{
                    alert("notc");                    
                    window.location="http://www.google.com";
                }
            }

To be more precise: your return from an asynchronous call "returns" nowhere. You probably want to call a callback function within the ajax success function. — random_user_name, May 13 '16 at 13:53
http://stackoverflow.com/questions/14220321/how-do-i-return-the-response-from-an-asynchronous-call — epascarello, May 13 '16 at 13:54
Please @epascarello understand me in detail. I am facing this problem for long time. — LOKESH, May 14 '16 at 05:39

score -1 · Answer 1 · answered May 13 '16 at 13:50

-1

You are trying to return two values after your first ajax call:

if(result=="yes"){                            
    return confirmval(companyname,username);
    return false;
}

This will just return the result of confirmval function (which appears to always return true), and the 'return false' line will never be run, thus it will always return true.

If you need that result=="yes" to return false, I might recommend something like:

if(result=="yes"){
    var confirmvalResult = confirmval(companyname,username);
    if(confirmvalResult) {
        return false;
    } else {
        // not sure what you want to do here
    }
}

answered May 13 '16 at 13:50

Brendan D.

96
7

that not the issue – LOKESH May 13 '16 at 13:51
Indeed, this is not the issue. Those returns go nowhere. – random_user_name May 13 '16 at 13:53
It is still worth noting that your confirmval function never returns false. If you add a callback function to actually receive your return value, it will still always return true, because you never return false. – Brendan D. May 13 '16 at 14:03

javascript validation and ajax call simultaneously not working

1 Answers1