In this line
public TreeSet<int> storage = new TreeSet<int>();
I get the following error when I try to compile:
error: unexpected type
public TreeSet<int> storage = new TreeSet<int>();
What do I need to do to fix this?
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You can only declare reference types as the arguments for generic type parameters. `int` is not a reference type. – RealSkeptic May 13 '16 at 21:28
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Think you have to Change from int to Integer – Jens May 13 '16 at 21:28
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1Refer to http://stackoverflow.com/questions/18021218/create-a-list-of-primitive-int – Tunaki May 13 '16 at 21:29
1 Answers
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Generics enable types (classes and interfaces) to be parameters when defining classes, interfaces and methods. So, parameters SHOULD not be primitive.
Change it to,
TreeSet <Integer> storage = new TreeSet<>();
(or)
Set <Integer> storage = new TreeSet<>();
Kris
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