Switch or If statements

Question

I'm trying to write an program that let's you choose between two things. But after executing the option that I chose, I want to be able to return the the beginning of that same option.

switch (option) {
case 1:
    System.out.println("Start of option 1");
    //option 1 will do things here
    System.out.println("End of option 1");
    //I want to return at the beginning of this case at the end of it
    break;

case 2:
    System.out.println("Start of option 2");
    //option 2 will do things here
    System.out.println("End of option 2");
    //I want to return at the beginning of this case at the end of it
    break;

default:
    break;
}

An option to get out of the selected case too. Also, would it be easier to implement what I'm trying to do with the use of if-statements instead?

Just use method in either switch or if and loop in there. – Tom May 13 '16 at 23:20 — Tom, May 13 '16 at 23:20

score 0 · Accepted Answer · answered May 13 '16 at 23:43

case 2:
    case2sub();
default:
    break;
}
}

public static void case2sub() {
    System.out.println("Start of option 2");
    //option 2 will do things here
    System.out.println("End of option 2");
    //I want to return at the beginning of this case at the end of it
    boolean end = false;
    System.out.println("QUIT? (Y/N)");
    keyboardInput =  new Scanner(System.in).nextLine();
    if (keyboardInput.equalsIgnoreCase("Y"))
            end = true;
    else{}
    if (end){}
    else
        case2sub();
}

If you put your cases in their own methods, you can call them recursively until you put in an exit statement. Recursion works and so does a while loop.

public static void case2sub() {
    boolean end = false;
    while (!end)
    {
    end = false;
    System.out.println("Start of option 2");
    //option 2 will do things here
    System.out.println("End of option 2");
    //I want to return at the beginning of this case at the end of it
    System.out.println("QUIT? (Y/N)");
    keyboardInput =  new Scanner(System.in).nextLine();
    if (keyboardInput.equalsIgnoreCase("Y"))
        end = true;
    }
}

You can exit this any number of ways. These are just two answers.

Recursion is a quite bad idea, since this can result in a `StackOverflowError`. Using a loop should be prefered here. — Tom, May 14 '16 at 01:28
I do not know what their code does, I found it a safe bet to show them more than one way. — DarkJade, May 16 '16 at 16:57

Switch or If statements

1 Answers1