PHP how to echo variable name

Question

I'm kinda confused in my case,

$counts="$s{$process[$count]}";

if i echo $counts with

echo "$counts";

it still showing the value, how can i echo $counts to show the variable name

$steamroller

(in this case the process is 'team', and count is 'roller')) instead of the value of the variable $system?

EDIT okay i found it by myself it should be

$counts='$s'.$process."[".$count."]";

thank you..

Just use `single quotes` instead of `double quotes` in echo `statement` plz check here: https://3v4l.org/VZHG8 — Ali, May 17 '16 at 04:53
Possible duplicate of http://stackoverflow.com/questions/255312/how-to-get-a-variable-name-as-a-string-in-php — Noman Ghani, May 17 '16 at 04:56
@Ali that's not what i mean, the $steamroller itself is a variable that has a value, so every time i echo $count it always showing the value of $steamroller instead of "$steamroller", the wrong thing i think is how i save the variable in $counts — unknown.person, May 17 '16 at 04:59
@FrayneKonok im sorry sir, i rate up your answer yesterday, maybe my internet connection is down, after i check again this time, my rate up and green check is missing, looks like it wasnt make it, sorry :) — unknown.person, May 18 '16 at 04:10

score 2 · Accepted Answer · answered May 17 '16 at 04:56

2

Just make this:

$s = 's';
$count = 1;
$process[$count] = 'teamroller';

echo $counts = "$$s{$process[$count]}"; // $steamroller

answered May 17 '16 at 04:56

Murad Hasan

score 2 · Answer 2 · answered May 17 '16 at 04:58

2

if you echo variable name in "" , php parse that variable an echo its value, if you want echo variable name with '' like this:

echo '$counts';

answered May 17 '16 at 04:58

Hossein

2 Answers2