How to sort keys of dict by values?

Question

I have a dict {'a': 2, 'b': 0, 'c': 1}.

Need to sort keys by values so that I can get a list ['b', 'c', 'a']

Is there any easy way to do this?

Answer 1

sorted_keys = sorted(my_dict, key=my_dict.get)

Answer 2

>>> d={'a': 2, 'b': 0, 'c': 1}
>>> [i[0] for i in sorted(d.items(), key=lambda x:x[1])]
['b', 'c', 'a']

Answer 3

try this:

import operator
lst1 = sorted(lst.items(), key=operator.itemgetter(1))

Answer 4

There's a simple way to do it. You can use .items() to get key-value and use sorted to sort them accordingly.

dictionary = sorted(dictionary.items(),key=lambda x:x[1])

Answer 5

>>> d = {'a':2, 'b':0, 'c':1}
>>> sor = sorted(d.items(), key=lambda x: x[1])
>>> sor
[('b', 0), ('c', 1), ('a', 2)]
>>> for i in sor:
...     print i[0]
...
b  
c 
a