What does this mean: int (*arr)[2]?

Asked May 18 '16 at 07:59

Active May 18 '16 at 11:46

Viewed 61 times

I know that the following would be an array of two elements each holding a pointer to an integer:

int* arr[2];

But I don't really understand what this does:

int (*arr)[2];

This is from the video course on data structures I'm watching right now, but I don't find the lecturer's explanation as to how exactly you should understand this kind of syntax all that clear, to say the least. Here's the YouTube link: Lecture 16: Dynamic Allocation (just click on the link and it will automatically take you to the moment he talks about it)

edited May 18 '16 at 11:46

asked May 18 '16 at 07:59

3

Pointer to an array of 2 `int`s. – haccks May 18 '16 at 08:00
I see now. This looks similar to how we declare function pointers. – May 18 '16 at 08:13
Do a favor to your self, do not watch that video again. – haccks May 18 '16 at 08:16
haccks, Why is that? – May 18 '16 at 08:17
2

Because 1) `a` is that video is an array not a pointer as he claims. 2) He is casting the value of `malloc` which is a bad practice. 3) He makes the explanation too complex for beginners and finally 4) He doesn't seem to be updated. – haccks May 18 '16 at 09:34

What does this mean: int (*arr)[2]?

0 Answers0