Multiple underscores at the end using REGEX?

Asked May 18 '16 at 21:41

Active May 18 '16 at 21:41

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I have a REGEX checker that is supposed to return true with the following conditions:

It has to begin with either an underscore '_' or a dot '.'

It has to be immediately followed by one or more occurrences of digits numbered 0-9

It can then have letters, both uppercase or lowercase, 0 or more in number

It can then end with an optional '_'

System.out.println(str.matches("^(_|\\.)[0-9]+[a-zA-z]*(_?)$"));

The above code works for every case except of cases where the string ends with several underscores, which should return a false, but strangely returns true. I tried several things but unfortunately haven't been able to make it work.

_08__ for example is returning true when it should be false.

asked May 18 '16 at 21:41

Enrique Medina

`[A-z]` is the culprit. Use `.matches("[_.][0-9]+\\p{L}*_?")`. It will also support all Unicode letters. Or replace `\\p{L}` with `[a-zA-Z]` to only support ASCII letters. – Wiktor Stribiżew May 18 '16 at 21:46
You are completely right it was just a Typo with the "z" instead of "Z" – Enrique Medina May 18 '16 at 21:55

Multiple underscores at the end using REGEX?

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