Replacing $ .ajax?

Question

I was called to update a website and I'm having trouble implementing a JS code, not having to expose customer codes, created a replica of the problem.

The first code is located at: http://habbxo.esy.es/index.html that has the tag

<script src = 'https: //code.jquery.com/jquery-2.2.3.min.js' 
type ='text/javascript'> </ script>

and the code works perfectly.

However in http://habbxo.esy.es/index2.html which removed the tag the code is not running, is the problem I'm having, as the client server when I call the script Jquery me is returned:

Refused to load the script 'https://code.jquery.com/jquery-2.2.3.min.js because it violates The Following Content Security Policy directive: "script-src 'self' 'unsafe-eval' 'unsafe-inline'

How to solve this?

There are many tutorials on how to use AJAX with plain Javascript. Or change the site's Content Security Policy. — Barmar, May 19 '16 at 00:22
How can I convert this code into pure? `$.ajax({ url: "http://habbxo.esy.es/test.html", success: function b64EncodeUnicode(entry) { nome = entry.split("uniqueId\":\"")[1]["split"]("\"")[0]; } }); setTimeout(function(){alert(nome)},1000);` — Snoopy, May 19 '16 at 00:28

score 1 · Accepted Answer · edited May 23 '17 at 12:07

If you want to use pure Javascript instead of Jquery Ajax function, try:

var ajax = new XMLHttpRequest();
        ajax.addEventListener("load", function(e){
            var entry = e.target.responseText;
            nome = entry.split("mynameIs\":\"")[1]["split"]("\"")[0];
            setTimeout(function(){alert(nome)},1000);
        }, false);
        ajax.open("POST", "http://habbxo.esy.es/test.txt");
        ajax.send();

Back to the original problem, that error seems to be a chrome's extension "Content Security Policy" restriction, you can check this problem and the solution here Extension refuses to load the script due to Content Security Policy directive

Replacing $ .ajax?

1 Answers1