Building ArrayList - Complex

Question

I am wanting to building an ArrayList, that later will be used to display information to a table.

The Issue is, I want my array to contain information that is in increments of 5000, up to 150+% the initial value.

IE:

User enters 100000.

The information in the array would look as such.

No code yet other than collect user input, just looking for a place to start with this.

Is the table going to have multiple columns? If so, a 2D array may be useful. — Arman, May 21 '16 at 17:57
well thats a simple `while/for` loop. and the arraylist i'm assuming would simply just be `ArrayList nums = new ArrayList();` — 3kings, May 21 '16 at 17:57
Yes, Arman it will have two columns. 3kings, I am give the while/for loop a go since that is about the only thing that has made since this far. — Matthew Kelsay, May 21 '16 at 18:07
Please show an example of a table (what you want it to output). — Arman, May 21 '16 at 18:08
if a user inputs 100002 the +50% (150%) would be 150003. **Its not a factor of 5000!!!! and 50% will not be reached by 5000-step, its at least 49.99871% ** — Grim, May 21 '16 at 18:11
Peter, I got that, it doesn't have to end with the figured value from the user input. — Matthew Kelsay, May 21 '16 at 18:20
@MatthewKelsay So is my solution what you needed? Or do I need to edit it — Arman, May 21 '16 at 18:23
But it could and that makes the question questionable. There is a clash between the relative-absolute 5000 and the relative-relative 50%. Remove the 50% and I will remove my downvote. — Grim, May 21 '16 at 18:23
@Arman as Peter pointed out this solution would be the result of 49.99871%. I would need the last value to end on 155002 not 150002. — Matthew Kelsay, May 21 '16 at 19:06

score 0 · Answer 1 · edited May 23 '17 at 12:19

0

int input = 100000;//user input
ArrayList<Integer> nums = new ArrayList<Integer>();
for(int i = 0; i <= (input/2); i+=5000){
     nums.add(input+i);
 }

This loop will get you started, if you'd like to have multiple columns, then you can use a 2D array instead. If you have further questions about 2D arrays, I would look here.

edited May 23 '17 at 12:19

Community

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answered May 21 '16 at 18:11

Arman

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If I input 100002 result will not be +50% – Grim May 21 '16 at 18:18
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Why do `double` math? `max / 2` would suffice. Why the extra parenthesis in `add((max+i))`? Just do `add(max+i)`. And the input isn't really "max", but rather "input", "start", or "min" if anything. – Andreas May 21 '16 at 18:25

score 0 · Accepted Answer · edited May 22 '16 at 18:05

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double num = sales * 1.5 + 5000;
ArrayList<Double> salesArList = new ArrayList<Double>();
double i = sales;
do{
    salesArList.add(i);
    i = i + 5000;
}while(i <= num);

edited May 22 '16 at 18:05

Laurel

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answered May 22 '16 at 16:59

Matthew Kelsay

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Building ArrayList - Complex

2 Answers2