Return a number of times of a specific string in python

Question

Return the number of times that the string "hi" appears anywhere in the given string.

count_hi('abc hi ho') → 1
count_hi('ABChi hi') → 2
count_hi('hihi') → 2

My code is below:

def count_hi(str): 
  sum = 0
  count = 1
   if "hi" in str:
    sum = sum + count
    count = 1 + count
   return count and sum

I'm trying to do it with character slicing. So I can test if there is a "h" and "i" in a word and counting the combination of "h" and "i" to make "hi" . So "hi" could be at the beginner, middle, and/or at the end of a bunch of words or letters and/ or by itself.

You don't have a loop - how could `sum` and `count` be anything other than `0` and `1` or `1` and `2`? This is on top of the syntax error in your function, with that unexpected indent. And you're also masking two built-ins. — TigerhawkT3, May 21 '16 at 23:36

score 3 · Accepted Answer · answered May 21 '16 at 23:31

3

You should use count() function for the string.

>>> "abc hi ho".count("hi")
1
>>> "ABChi hi".count("hi")
2

answered May 21 '16 at 23:31

Laszlowaty

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score 0 · Answer 2 · answered May 21 '16 at 23:33

0

str.count(sub[, start[, end]])

Return the number of non-overlapping occurrences of substring sub in the range [start, end]. Optional arguments start and end are interpreted as in slice notation.

answered May 21 '16 at 23:33

inbinder

692
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Return a number of times of a specific string in python

2 Answers2