I am wondering whether the following is defined behavior per the Promise specification:
var H = function (c) {
this.d_p = Promise.resolve();
this.d_c = c;
};
H.prototype.q = function () {
var s = this;
return new Promise(function (resolve) {
s.d_p = s.d_p.then(function () { // (1)
s.d_c({
resolve: resolve
});
});
});
};
var a,
h = new H(function (args) { a = args; }),
p;
Promise.resolve()
.then(function () {
p = h.q();
})
.then(function () { // (2)
a.resolve(42);
return p;
});
The question is whether it's guaranteed that the then
callback marked (1)
is called before the then
callback marked (2)
.
Note that both promises in question are instantly resolved, so it seems to me like the (1)
then callback should be scheduled as part of calling h.q()
, which should be before the promise used to resolve (2)
is resolved, so it should be before (2)
is scheduled.
An example jsfiddle to play about with: https://jsfiddle.net/m4ruec7o/
It seems that this is what happens with bluebird >= 2.4.1, but not prior versions. I tracked the change in behavior down to this commit: https://github.com/petkaantonov/bluebird/commit/6bbb3648edb17865a6ad89a694a3241f38b7f86e
Thanks!