First of all, I want to send parameters from html to Servlet and it works. Then I create an array from parameters and I want to send that array to another servlet. and just print it in Servlet2. Here is my code:
public void doGet(HttpServletRequest request,
HttpServletResponse response) throws ServletException, IOException {
//System.out.println("XML servlet called!");
response.setContentType("text/html");
response.getWriter();
//read value from selection
String videoname = request.getParameter("video");
String videoformat = request.getParameter("format");
String videoquality = request.getParameter("quality");
//System.out.println("Name" + videoname);
//System.out.println("format" + videoformat);
//System.out.println("quality" + videoquality);
String [] chain1 = {"v1","f1","q1"};
String [] chain2 = {"v1","f1","q2"};
if (videoname.equals(chain1[0]) && (videoformat.equals(chain1[1])) && (videoquality.equals(chain1[2])) ){
request.setAttribute("chain",chain1);
}
}else if (videoname.equals(chain2[0]) && (videoformat.equals(chain2[1])) && (videoquality.equals(chain2[2])) ){
request.setAttribute("chain",chain2);}
RequestDispatcher dispatch = request.getRequestDispatcher("/Servlet2");
dispatch.forward(request, response);
And in Second Servlet , my code is :
String value = (String)request.getAttribute("chain");
System.out.println("Chain is" + value);
My problem is this is doesn`t work. I have 2 problems. 1) how to send attribiute 2) is that possible to see the result in servlet2 in the same mashin? becuse I just create another class wich name is Servlet2 on the same project and define the name and the path in web.xml. Is that right approch?