convert exponential to float in time.clock()

Question

Here is my code

import time
t0=time.clock()
t1=time.clock()
time_difference = t1-t0
print time_difference

and output is

9.99999999998e-07

i want to assign value of t1-t0 to time_difference in float format having 2 digits after decimal how can i do that

Already asked here: http://stackoverflow.com/questions/455612/limiting-floats-to-two-decimal-points — Nevenoe, May 27 '16 at 10:16

anumi · Answer 1 · 2016-05-27T10:20:51.623

1

If you wish to print the value, you can use formatted output. This will print float values with two decimal digits after the dot: print "%.2f" % time_difference.

If you wish to update time_difference as a float value with two digits, you can use the round function (see https://docs.python.org/2/library/functions.html#round): time_difference = round(time_difference, 2).

edited May 27 '16 at 10:20

answered May 27 '16 at 10:13

anumi

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but i want to assign difference so that if i want i can compare the difference with float value – Om Prakash Kumar May 27 '16 at 10:19
I expanded my answer for this case. – anumi May 27 '16 at 10:23

score 1 · Answer 2 · edited Jul 13 '18 at 13:43

1

The simplest way to convert an exponential to float is

e_variable = 4.3e-05 

convert_to_float = str('%.08f' % e_variable)

print convert_to_float

edited Jul 13 '18 at 13:43

Benkerroum Mohamed

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answered Jul 13 '18 at 13:36

Guilherme Pedriconi

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convert exponential to float in time.clock()

2 Answers2