NullPointerException on FileInput/OutputStream on jar

Question

I'm working on application that causes me many problems when working

file1 = "src\\sga\\facturation\\data.ser";
FileInputStream fis = new FileInputrStream(file1);//this works fine on NetBeans

I tried

file1 = "data.ser";
InputStream fis = ClassLoader.getSystemClassLoader().getResourceAsStream(file1);

But nothing; I tried also to change the repertory's path, it told me file not found, I tried even to force the repertory in C:\Folder; where I put my files but nothing works. I tried to delete those lines to see if FileOutputStream works, but it's not the case :( Here's which works on NetBeans

 ObjectOutputStream oos = new ObjectOutputStream(new FileOutputStream(file2));

This is my repertory

My Path

Thanks for helping RELATED POSTS NEVER TOLD ME A SOLUTION WHICH WORK, SO IF YOUR ATTENTION WAS TO PUT A -1 ON BEGINING, DO IT AND LEAVE !

is your file, that you ar trying to load in your Jar or outside next to the Jar? also do you have the src file next the jar when you compile it? — Samuel Kodytek, May 29 '16 at 08:16
My file must be in the same directory than classes (all classes are also in src/sga/facturation) — John Doe, May 29 '16 at 08:18
Are you sure that your build system has actually put the file into JAR? Rename it to *.ZIP and inspect with an archive manager. — Basilevs, May 29 '16 at 08:48
Affirmative, all files are in the same folder with classes ! — John Doe, May 29 '16 at 08:56
I tried this, now it gives me same error on declaration of the ObjectInputStream; should I use another thing or .. ?! — John Doe, May 29 '16 at 09:05

score 1 · Answer 1 · answered May 29 '16 at 08:23

1

Normally you would load a file that's located in your jar with: InputStream is = this.getClass().getResourceAsStream("my/path/to.file"); but you have to be careful that if the jar or the directory the jar is in has a space it bugs out sometimes. I remember trying this like a year ago. Try the jar and the file thats its located in renaming it.

Their might also be a problem with dir permissions, try running your jar like a administrator

answered May 29 '16 at 08:23

Samuel Kodytek

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My path to the file is `"src\\sga\\facturation\\data.ser"` but the jar when unzipin, doesn't contain src .... – John Doe May 29 '16 at 08:28
@John Doe in the src you should have your .class files and eventually sga//factuarion/data.ser or something like that :P check if you have your files really in your netbeans src folder – Samuel Kodytek May 29 '16 at 08:30

score 0 · Answer 2 · answered May 29 '16 at 08:29

0

FileInputStream resolves relative path based on current working directory. In your IDE working directory may be different from what it is for standalone program. Use absolute path instead.

answered May 29 '16 at 08:29

Basilevs

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When I try to this, and printing the patrh I got this: `C:\bla\bla\bla\SGA-Facturation.jar!\sga\facturation\data.ser` And a syntax error on the path :/ – John Doe May 29 '16 at 08:33
Well, you can't read archives using File API. URL.openStream() may work – Basilevs May 29 '16 at 08:44
How could I use it? will the URL be just the name of file, or all the path? with ou wothout src ?! – John Doe May 29 '16 at 08:50

NullPointerException on FileInput/OutputStream on jar

2 Answers2