Match Regex unless leading character is a space

Question

I have three strings, which only two of them must match:

c = kj.a(yj.class, ki.f);  //Should match entirely
k = kj.h(yj.class, ki.b);  //Should match entirely
Object a0 = this.l.a(yj.class, this.bo().b(0.5, 0.0, 0.5)).iterator(); // Should NOT match at all

In order to differentiate the first two strings from other strings that could be present, I wrote this expression:

(\w* = [^;]*\.\w\(yj\.class, [^;]*\);)

But right now, what happens is that the first two strings get matched correctly, but the last gets matched partially, because it has somewhat the same pattern as the first two (the last it should not get matched at all); the last is matched as such: a0 = this.l.a(yj.class, this.bo().b(0.5, 0.0, 0.5)).iterator();

How can I prevent the last string from being matched entirely? I am thinking I should check if the fist character is not a space () (or contains one...)

Take a look at [anchors](http://www.regular-expressions.info/anchors.html). — Sebastian Proske, May 29 '16 at 17:34
`^\w* = [^;]*\.\w\(yj\.class, [^;]*\);)` . ^ -> should start with this. But \w* means zero or more occurrences. are you sure? — gaganso, May 29 '16 at 17:35
@SilentMonk When I use that, the first string gets matched, but the second string is not matched anymore? Probably something to do with \n...? — Momo, May 29 '16 at 17:42
@Momo, can you please post the code snippet where you are doing regex match? — gaganso, May 29 '16 at 17:43
`(^[^ ]+ = [^;]*\.\w\(yj\.class, [^;]*\);)` [Look](https://regex101.com/r/bU7wT2/1) — dawg, May 29 '16 at 17:49
will work fine..don't worry..check **[here](https://regex101.com/r/wR8oR7/1)** — rock321987, May 29 '16 at 17:50
@Momo, I have consolidated it as an answer. As you suggested it needed multiline matching. — gaganso, May 29 '16 at 17:54

score 0 · Answer 1 · edited Jun 20 '20 at 09:12

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/^\w+ = [^;]*\.\w\(yj\.class, [^;]*\);/mg

m - multiline match.

g - global

edited Jun 20 '20 at 09:12

Community

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answered May 29 '16 at 17:49

gaganso

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dawg · Answer 2 · 2016-05-29T17:56:38.120

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/(^[^ ]+ = [^;]*\.\w\(yj\.class, [^;]*\);)/gm

Demo

edited May 29 '16 at 17:56

answered May 29 '16 at 17:50

dawg

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Could you please add some context to this regular expression? – pppery May 30 '16 at 01:35

score 0 · Answer 3 · answered May 29 '16 at 17:52

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this regex will only take the lines that do not contain a number before the "="

[a-z]\s=[^;]*\.\w\(yj\.class, [^;]*\);

answered May 29 '16 at 17:52

snazzyalien

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Match Regex unless leading character is a space

3 Answers3