convert float value to str without rounding in python3

Question

I am having a calculation problem.

main_value = 4.4789

Now i want to compare this value with a user input value

user_input = 4.5

if main_value >= user_input:
    print('yes')
else:
    print('no')

The problem is i'm displaying the main_value in single digit precision in GUI (4.4789 gets rounded and displayed_value = 4.5)

so when comparison is made the display shows 4.5 but prints NO...

how do i solve this!!!

Should i use Decimal module (please with an example) or any other simple method is there??

Thanks!!

http://stackoverflow.com/questions/34814941/python-format-float-to-decimal-in-pyqt — Paul, May 31 '16 at 07:35
But that method rounds the value.. I dont want to round the value.. Display as it is with 1 decimal places.. — Daniel Sampras, Jun 01 '16 at 04:20
If you stay under the automatic round made by Python on float, you can use `str(f)[:str(f).index('.')+2]`. — Paul, Jun 01 '16 at 08:13

Paul · Accepted Answer · 2016-06-01T08:16:47.830

0

s[:s.index('.')+1+n]

where s is your string representing your float and n the number of digit you want to keep after the .

edited Jun 01 '16 at 08:16

answered Jun 01 '16 at 08:07

Paul

1 Answers1