Url encode using python 2.7

Question

>>> import httplib
>>> x = httplib.HTTPConnection('localhost', 8080)
>>> x.connect()
>>> x.request('GET','/camera/store?fn=aaa&ts='+str.encode('2015-06-15T14:45:21.982600+00:00','ascii')+'&cam=ddd')
>>> y=x.getresponse()
>>> z=y.read()
>>> z

'error: Invalid format: "2015-06-15T14:45:21.982600 00:00" is malformed at " 00:00"'

And the system show me this error. As i want to encode this format to this: 2015-06-15T14%3A45%3A21.982600%2B00%3A00

score 9 · Accepted Answer · edited May 23 '17 at 12:24

9

>>> import urllib
>>> f = { 'fn' : 'aaa', 'ts' : "2015-06-15T14:45:21.982600+00:00"}
>>> urllib.urlencode(f)

from:

How to urlencode a querystring in Python?

edited May 23 '17 at 12:24

Community

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answered May 31 '16 at 09:14

Destrif

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Just: x.request('GET','/camera/store?fn=aaa&ts='+urllib.urlencode(f)+'&cam=ddd'), also add cam and 'ddd' to the data... – Destrif May 31 '16 at 09:36

score 4 · Answer 2 · answered May 31 '16 at 09:35

4

url = "http://example.com?p=" + urllib.quote(query)

it works with this!

answered May 31 '16 at 09:35

Kevin Kai

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Url encode using python 2.7

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