There a random 'b' that shouldn't be there

Question

So I am playing around with UDP communication in python and I finally got a little messaging thing to work but on the client side, there is a random 'b' here is my code

udpServer.py:

import socket
import time
import os
import getpass

userNonByt = getpass.getuser()
username = bytes(userNonByt, 'utf-8')
HOST = "localhost"
PORT =  5454
HOST = bytes(HOST, 'utf-8')
bytes(PORT)
s = socket.socket(socket.AF_INET,socket.SOCK_DGRAM)

def setmsg():
    os.system('cls')
    #asks user for there text to send
    data = input("Send: ")
    #converts there text to bytes so it can be sent in the UDP Packet
    text = bytes(data, 'utf-8')
    #sends the users text
    s.sendto(username,(HOST,PORT))
    s.sendto((text),(HOST,PORT))
    #brings you back to the begining of this function
    setmsg()


setmsg()

udpClient.py:

import socket


HOST = 'localhost'
PORT =  5454
HOST = bytes(HOST, 'utf-8')

s = socket.socket(socket.AF_INET,socket.SOCK_DGRAM)

s.bind((HOST,PORT))

while 1:
    print (s.recv(30))

Can someone please help me?

switch to Python 2.7 and the `b` (in `b"..."`) will go away ;-) — thebjorn, May 31 '16 at 19:51
`b"..."` just means it is a `bytestring` as opposed to a `unicode string` ... — Joran Beasley, May 31 '16 at 19:53
The description of a 'random b' is particularly uninformative. Good thing we are good at guessing, or we'd have closed this post hours ago. — hpaulj, May 31 '16 at 20:41

score 1 · Accepted Answer · answered May 31 '16 at 20:01

1

What you are printing is encoded. Use .decode() to print the actual string.

while 1:
    print(s.recv(30).decode())

answered May 31 '16 at 20:01

ritlew

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There a random 'b' that shouldn't be there

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