How to use an objects' property as the key for @CachePut?

Question

public interface MyRespository extends CrudRepository<MyEntity, Long> {
    @CachePut(value = "mycache", key = "id")
    @Override
    public <S extends MyEntity> S save(S entity);
}

@Entity
public class MyEntity {
    @Id
    private Long id;

    public Long getId() { return id; }
    public void setId(Long id) { this.id = id; }
}

Result:

org.springframework.expression.spel.SpelEvaluationException: EL1008E:(pos 0): Property or field 'id' cannot be found on object of type 'org.springframework.cache.interceptor.CacheExpressionRootObject' - maybe not public?

`org.springframework.expression.spel.SpelEvaluationException: EL1007E:(pos 0): Property or field 'id' cannot be found on null` — membersound, Jun 01 '16 at 15:54
No I'm not. It's jujst that the `#entity.id` cannot be resolved somehow. The case works fine when I remove the `@CachePut` annotation. — membersound, Jun 01 '16 at 16:05

score 1 · Accepted Answer · answered Jun 02 '16 at 08:22

1

Accessing the object by index with key = "#a0.id" worked, but I still don't know why it's not possible to access the object by its name.

answered Jun 02 '16 at 08:22

membersound

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You can use #id instead – user12384512 Feb 21 '17 at 15:59

How to use an objects' property as the key for @CachePut?

1 Answers1