Save the ith row in the first column in a variable

Asked Jun 01 '16 at 16:50

Active Jun 01 '16 at 16:50

Viewed 23 times

We are trying to run this Script:

    #!/bin/bash
CrntDir=$(pwd)
cd $CrntDir
i=0
 while read p; do
i=$((i+1))
echo $i
        ReactionNr=$(awk 'FNR == i {print $1}' $CrntDir/allCcurv.dat)
echo $ReactionNr
#   RLabel=$(grep -r '$ReactionNr' $CrntDir/newfile | awk '{print $2}')
#echo $RLabel
#        awk '{print $0 $RLabel}' $CrntDir/allCcurv.dat
 done <allCcurv.dat

so that it takes the value in the first column at the ith row and saves it in the variable ReactionNr. Then it should take that var and read a string that starts with that variable and in the end append that string to the first file. The Context is, that we need to sort some values from our experiements.

In this state the code just counts from i = 1 to i = #ofrows.

What are we doing wrong? And is the Expression FNR == i the right way to do what we want? (Found it somewhere in a Forum)

Thanks

asked Jun 01 '16 at 16:50

Tuni

thanks! now we cant figure out how to use ReactionNr in the grep Command... Its giving back empty lines – Tuni Jun 01 '16 at 17:00
You'll need to switch those single quotes to double quotes. Single Quotes in bash don't allow variable expansion. – JNevill Jun 01 '16 at 17:04
Thank you it worked perfect :) – Tuni Jun 02 '16 at 11:59

Save the ith row in the first column in a variable

0 Answers0