How do I open all files in a directory in python?

Question

I have the code

import os

def Load():
    for filename in os.listdir("directoryPath"):
        content = open(filename, "r")
Load()

And I would like to know how to load the files that filename returns, at the moment I just get an error saying FileNotFoundError: [Errno 2] No such file or directory: 'Adjectives.txt'

You might need to append the directory name to the front of the filename — OneCricketeer, Jun 02 '16 at 00:47
looks like youre just passing a string "directoryPath" to `listdir` — Simon, Jun 02 '16 at 00:48

score 3 · Accepted Answer · answered Jun 02 '16 at 00:48

3

os.listdir() returns only the filename, not the full path. You need to pass the whole path to open. You can use os.path.join to combine directory and filename:

content = open(os.path.join('directoryPath', filename), 'r')

answered Jun 02 '16 at 00:48

niemmi

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Just one small remark: The name `content` is misleading because it will not contain the content of the file. – Matthias Jun 02 '16 at 08:16
@Matthias: I agree but decided to keep the variable names the same as in the question – niemmi Jun 02 '16 at 09:20

How do I open all files in a directory in python?

1 Answers1