Subtracting 1 second from time in Python

Asked Jun 02 '16 at 14:10

Active Jun 02 '16 at 15:44

Viewed 51 times

I am new to Python. I would like to subtract 1 second from a time. I tried the code below:

inp_time = "15:30:40.740"
out_time = datetime.time(int(inp_time[:2]), int(inp_time[3:5]),   int(inp_time[6:8]), int(inp_time[-3:]))
x=1
from_time = datetime.time(out_time) - datetime.timedelta(seconds=x)

I get error:

TypeError: an integer is required (got type datetime.time).

edited Jun 02 '16 at 15:44

Gustavo Morales

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asked Jun 02 '16 at 14:10

user6357081

Use datetime.datetime.time – Tilak Madichetti Jun 02 '16 at 14:14
2

Change `datetime.time(out_time)` to just `out_time`, then see [this question](http://stackoverflow.com/questions/12448592/how-to-add-delta-to-python-datetime-time) for your next problem. – glibdud Jun 02 '16 at 14:25
Thanks, I got it working now! – user6357081 Jun 02 '16 at 15:29

Subtracting 1 second from time in Python

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