Object without class: adding new fields and returning as JSON

Question

My question is a variation of the following post here added to JSON logic. I´m using PHP 5.6.22

I need to build a class without an object at runtim to build a JSON object of same type to be returned to the client. My code:

public static function getData()
{
    $columns = array ("Name", "Address", "Age" );
    $values  = array ("John", "A Ave 222", 32 );

    $ret = (object)[];
    $index = 0;

    foreach ($columns as $col)
    {
        $value = $values[$index++];
        $ret[] = (object) [$col => $value]; // Error here
    }

    return json_encode($ret);
}

When running that I get the following error:

<b>Fatal error</b>:  Cannot use object of type stdClass as array in <source filename> on line <linenumber>

Help appreaciated to solve that...

`$ret = (object)[];` means `$ret` is an instance of `stdClass` (though god know why you're even doing that), then later you use `$ret[] = ` which you can't do because `$ret` is an object, not an array. — Jonnix, Jun 02 '16 at 17:57
1. Do you use PHP7? 2. Did you mean an object without a class? — guessimtoolate, Jun 02 '16 at 17:59
Post edited: `splash`: I´m copying from a VM without copy+paste feature - code fixed; `guessimtoolate`:Using PHP 5.6.22; `Jon`: good point - this shall be the problem, but: how to add a new property to `stdClass` ? — Mendes, Jun 02 '16 at 18:03
If you only need it to encode it to JSON why not just use an associative array? It'll be encoded to a JSON object. — guessimtoolate, Jun 02 '16 at 18:05

score 1 · Accepted Answer · answered Jun 02 '16 at 18:07

1

In PHP you can add new property to array just by setting it

$columns = array ("Name", "Address", "Age" );
$values  = array ("John", "A Ave 222", 32 );

$ret = (object) [];
$index = 0;

foreach ($columns as $col)
{
    $value = $values[$index++];
    // You can create and add new property to object in php by such way
    $ret->$col = $value; 
}

echo json_encode($ret);  // {"Name":"John","Address":"A Ave 222","Age":32}

answered Jun 02 '16 at 18:07

splash58

26,043
3
22
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Glad than could help. Good luck! – splash58 Jun 02 '16 at 18:29

score 0 · Answer 2 · answered Jun 02 '16 at 18:11

0

How about:

public static function getData()
{
    $data = [
        "Name" => "John",
        "Address" => "A Ave 222",
        "Age" => 32,
    ];
    return json_encode($data);
}

?

answered Jun 02 '16 at 18:11

guessimtoolate

8,372
2
18
26

Object without class: adding new fields and returning as JSON

2 Answers2