python svgwrite can't add class attribute?

Question

I'm trying to correct the following code:

import svgwrite
dwg = svgwrite.Drawing('test.svg', profile='tiny')
dwg.add(dwg.circle((10, 0), 20 , fill='rgb(0,0,255)', id='rrr', class='#t'))
dwg.save()

I get the following error:

dwg.add(dwg.circle((10, 0), 20 , fill='rgb(0,0,255)', id='rrr', class='#t'))
                                                                    ^
SyntaxError: invalid syntax

Why is that? Apparently svgwrite can't add a class attribute to elements

`class` is a keyword in Python, try `**{'class': '#t'}))` – Ashwini Chaudhary Jun 03 '16 at 08:18 — Ashwini Chaudhary, Jun 03 '16 at 08:18

score 7 · Answer 1 · answered Jun 03 '16 at 08:44

7

According to the svgwrite documentation you must add a trailing underscore to attributes which are python keywords. So the correct code would be:

dwg.add(dwg.circle((10, 0), 20 , fill='rgb(0,0,255)', id='rrr', class_='#t'))

answered Jun 03 '16 at 08:44

Robert Longson

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python svgwrite can't add class attribute?

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