why destructor id printing message again in python?

Question

here is my code

class third:

    def __init__(self):
        print("Cons is called")

    def __del__(self):
        print("desc is called")

    def setName(self,firstName,lastName):
        self.firstName=firstName;
        self.lastName=lastName;

    def displayName(self):
        print(self.firstName,' ' ,self.lastName)

ob=third(); 
ob.setName('gaurav','sharma');
ob.displayName()
ob.__del__()
ob.displayName();

and output is

  Cons is called
  gaurav   sharma  
  desc is called
  gaurav   sharma
  desc is called

i have destroyed object by using del and then tried to call displayname function again still it is providing distroyed values and now i m confused weather the object is destroid or not.

`__del__()` is called by each destruction of instance. Calling of `__del__()` doesn't destroy the object self — qvpham, Jun 03 '16 at 10:04
Note that having setters and getters is not Pythonic - use `@property`. — jonrsharpe, Jun 03 '16 at 10:24

Selcuk · Accepted Answer · 2016-06-03T10:04:44.007

1

You should not call __del__() directly as it will only run that method but won't actually delete the object. Use the del statement to delete an object:

>>> del ob
>>> ob
>>> NameError: name 'ob' is not defined

edited Jun 03 '16 at 10:04

answered Jun 03 '16 at 10:01

Selcuk

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`del` is not a function, so no parentheses please. – Daniel Jun 03 '16 at 10:03
@Daniel You are right, fixed. Thanks for the heads up. – Selcuk Jun 03 '16 at 10:04
@deniel it's working. – Tiger Jun 03 '16 at 10:05

why destructor id printing message again in python?

1 Answers1